1/27/2009 8:06:21 AM

You would need to move the initialization of r outside the loop.

Each execution of the loop creates a new instance of the random number generator, re-initializing the seed value to a value based on the system clock. While single-stepping through the code, enough time passes between one execution and the next to allow for a different seed value to be added. When ran outside of debug, the time delay is too small to actually result in a new value for the seed, and thus you get a repeating series of values.

Personally, I move code declarations such as this outside of loops - but your style may differ. However, by always having the initializer code (the ctor) outside of the loop, you tend to reduce these types of errors.

Random r = new Random();
int intRandomElement;
for (int i = 0; i < 5; i++)
{
//Generating a Random number between 0 and 100000
intRandomElement = r.Next(1, 100000);
Console.WriteLine(intRandomElement);
}

Steven Foust

7/13/2009 5:56:06 AM

you can use this code.
for (int i = 0; i < 5; i++)
{
//Generating a Random number between 0 and 100000
int intRandomElement;
Random r = new Random();
intRandomElement = r.Next(1, 100000);
Console.WriteLine(intRandomElement);
Console.ReadKey();


}

Ashish Kapoor